262A - Roma and Lucky Numbers - CodeForces Solution


implementation *800

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Python Code:

n, k = list(map(int, input().split()))
w = input().split()

d = 0
for i in range(n):
    c = 0
    for j in range(len(w[i])):
        if w[i][j] == '4' or w[i][j] == '7':
            c += 1
    if c > k:
        d += 1
print(n-d)

C++ Code:

#include<bits/stdc++.h>
using namespace std;

int main() {
    int n, k;
    cin >> n >> k;
    int ans = 0;
    for(int i = 0; i < n; i++) {
        string s;
        cin >> s;
        int c = 0;
        for(auto i:s) {
            if(i=='4' or i=='7') {
                c ++;
            }
        }
        if(c<=k) {
            ans ++;
        }
    }
    cout << ans;
}


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